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Answered by
0
CB =5 cm
by Pythagoras theorem
tan theta = 5/5√3
=1/√3
so, theta =30
by Pythagoras theorem
tan theta = 5/5√3
=1/√3
so, theta =30
aryan256:
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Answered by
2
In triangle BDC;
By Pythagoras theorem
(BC)^2=(CD)^2+(BD)^2
=16+9
BC=5cm
Now in triangle ABC
tan theta =BC/AB
=5/5root3
=1/root 3
tan theta = tan30°
on comparing
theta=30°
By Pythagoras theorem
(BC)^2=(CD)^2+(BD)^2
=16+9
BC=5cm
Now in triangle ABC
tan theta =BC/AB
=5/5root3
=1/root 3
tan theta = tan30°
on comparing
theta=30°
mark this answer as brainliest
okay
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