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Let x be candidates applied and 60/100x=.6x candidates selected.
(x+70)(1–60/100)=.6x-50
.4x+28=.6x-50
.2x=78 or x=390
Candidates who applied =390
(x+70)(1–60/100)=.6x-50
.4x+28=.6x-50
.2x=78 or x=390
Candidates who applied =390
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Answer:
Let the number of candidates be X. Hence selected candidates =0.60X. Equation
0.60X - 50 =0.40( X+70)
=0.20X =78
Therefore X = 780 ÷2 = 390.
Hence originally 390 candidates had applied for the post.
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