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here's your answer in the attachment
and the last letter of 1st line is a
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It is instructed to subtract (2a - 3b + 4c) from the sum of (a + 3b - 4c), (4a - b+9c) and (-2b + 3c - a).
So, First we will do the sum of the three given polynomials,
Sum = (a + 3b-4c) + (4a-b 9c) + (-2b + 3c-a)
= (a + 4a - a) + (3b - b- 2b) + (-4c+ 9c + 3c)
= 4a + 8c
Now, we can perform the subtraction,
therefore, Required difference
= (4a +8C) - (2a - 3b + 4c)
= 4a + 8c 2a + 3b-4c
= 2a + 3b + 4c
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