Math, asked by saishasharma23, 30 days ago

Answer and Solve the following:​

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Answers

Answered by kiran12355
1

Step-by-step explanation:

1)3x^2+9x+6

3x^2+6x+3x+6=0

3x(x+2)+3(x+2)=0

(3x+3)(x+2)=0

x=-3/3. x= -2

x= -1. or. x= -2

2)9x^2-6x+1

9x^2-6x+1=0

9x^2-3x-3x+1=0

3x(3x-1)-1(3x-1)=0

(3x-1)(3x-1)=0

x=1/3. or. x=1/3

3)6x^2-7x-3

6x^2-9x+2x-3=0

3x(2x-3)+1(2x-3)=0

(3x+1)(2x-3)=0

x= -1/3. or. x=3/2

4)x^2-7

x^2-(√7)^2=0

(x-√7)(x+√7)=0

x= √7. or. x= -√7

5)x^2+8x+15

x^2+5x+3x+15=0

x(x+5)+3(x+5)=0

(x+3)(x+5)=0

x= -3. or x= -5

6)2x^2-5x-12

2x^2-8x+3x-12=0

2x(x-4)+3(x-4)=0

(2x+3)(x-4)=0

x= -3/2. or. x=4

7)y^2+3y-10

y^2+5y-2y-10=0

y(y+5)-2(y+5)=0

(y-2)(y+5)=0

y=2. or. y= -5

8)25a^2-35a+12

25a^2-15a-20a+12=0

5a(5a-3)-4(5a-3)=0

(5a-4)(5a-3)=0

a=4/5. or. a=3/5

Answered by nethraeval
0

Answer:

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