Question

answer answer answer​

Answer 1

Answer:

4. ÷3 because I have a great time

Answer 2

x is not a square of another number. We cannot find its square root.

Let's think outside the box. If you square then find its square root, you get the same number if it was a positive number or zero.

And we can use algebra, to find $\boxed{(\sqrt{x} +\frac{2}{\sqrt{x} } )^2}$

$\boxed{(\sqrt{x} +\frac{2}{\sqrt{x} } )^2=x+4+\frac{4}{x} }$ ... 1

$\boxed{\frac{4}{x} =8+\sqrt{60}}$ ... 2

With 1 and 2 we can find its squared value:

→ $\boxed{(8-\sqrt{60} )+4+(8+\sqrt{60})}$

→ $\boxed{20}$ is the squared value.

Now we may find the square root. (Square, then find square root.)

Since the square root is always positive, the value of its square root is $\boxed{2\sqrt{5} }$.

∴$\boxed{\sqrt{x} +\frac{2}{\sqrt{x} } =2\sqrt{5}}$

Therefore, the answer is $\boxed{\sqrt{5}}$.