Math, asked by Atharvakote, 1 year ago

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Answered by riya18325
3
Let three no. are x-1,x,x+1
Sum of the numbers 3x >45 but 3x < 54.................(1)
The condition give in equation (1) is satisfied if 3x=48 or 3x=51
If required sum is 48, x=16, the numbers are 15, 16, 17
If required sum is 51, x= 17, then numbers are 16, 17, 18

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Answered by yahootak
2
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Let the smallest whole no. be = x

So,
Three consecutive whole numbers
= x + (x+1) + (x+2)

\bold{CONDITION \:GIVEN:}
✒Sum of numbers is less than 45 and greater than 54

So,
45 < x + (x + 1 ) + (x + 2) < 54

45 < 3x + 3 < 54

Subtracting 3

(45-3) < (3x + 3 - 3) < (54-3)

42 < 3x < 51

Dividing 3

42/3 < 3x/3 < 51/3

14 < x < 17

So,x is greater than 14 and smaller than 17

So, x can be = 15,16

i.e

14 < 15 < 16 < 17

If
x = 15
x+1 = 15 + 1 = 16
x+2= 15 + 2 = 17

if
x=16
x+1=16 + 1 = 17
x+2=16 + 2 = 18

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\bold{Answer:}

15,16,17

or

16,17,18

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