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Step-by-step explanation:
In ∆abc and ∆bdc
Ad = ad ( common )
Angle ADB = angle ADC ( given )
Angle BAD = angle DAC ( given )
-- ∆abc ≈ ∆bdc (SAS congruence)
-- AB=AC (cpct)
--∆abc is an isosceles triangle ( opp. Sides of triangle are equal )
Hence proved.....!!
Hope it helps
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Answered by
0
Answer:
Step-by-step explanation:
In ∆abc and ∆bdc
Ad = ad ( common )
Angle ADB = angle ADC ( given )
Angle BAD = angle DAC ( given )
-- ∆abc ≈ ∆bdc (SAS congruence)
-- AB=AC (cpct)
--∆abc is an isosceles triangle ( opp. Sides of triangle are equal )
Hence proved.....!!
Step-by-step explanation:
In ∆abc and ∆bdc
Ad = ad ( common )
Angle ADB = angle ADC ( given )
Angle BAD = angle DAC ( given )
-- ∆abc ≈ ∆bdc (SAS congruence)
-- AB=AC (cpct)
--∆abc is an isosceles triangle ( opp. Sides of triangle are equal )
Hence proved.....!!
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