Math, asked by apexa211180, 8 months ago

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Answered by aepbcccpwd
0

Answer:

Step-by-step explanation:

In ∆abc and ∆bdc

Ad = ad ( common )

Angle ADB = angle ADC ( given )

Angle BAD = angle DAC ( given )

-- ∆abc ≈ ∆bdc (SAS congruence)

-- AB=AC (cpct)

--∆abc is an isosceles triangle ( opp. Sides of triangle are equal )

Hence proved.....!!

Hope it helps

Have a great day ahead ♥️

..!

Answered by Anonymous
0
Answer:

Step-by-step explanation:

In ∆abc and ∆bdc

Ad = ad ( common )

Angle ADB = angle ADC ( given )

Angle BAD = angle DAC ( given )

-- ∆abc ≈ ∆bdc (SAS congruence)

-- AB=AC (cpct)

--∆abc is an isosceles triangle ( opp. Sides of triangle are equal )

Hence proved.....!!
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