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Answered by XBarryX
0

Answer:

Given :-

A  10 hectare field is reaped by 2 men, 3 women and 4 children in 10 days. If a man, a woman and a child work in the ratio 5:4:2

To Find :-

A 16 hectare field will be reaped by 6 men, 4 women and 7 children in:

Solution :-

Ratio = 5:4:2

Finding all people work in one day

For men

Work of men in one day = Men in ratio × Given men in 10 hectare

Work of men in one day = 5 × 2

Work of men in one day = 10

For women

Work of women in one day = Women in ratio × Given Women in 10 hectare

Work of women in one day = 4 × 3

Work of women in one day = 12

For children

Work of children in one day = Children in ratio × Given Children in 10 hectare

Work of children in one day = 2 × 4

Work of children in one day = 8

Now

(Men + Women + Children) × Time/Field reaped

(10 + 12 + 8) × 10/10

30 × 10/10

300/10

Let the time be t

For men

Work of men in one day = Men in ratio × Given men in 16 hectare

Work of men in one day = 5 × 6

Work of men in one day = 30

For women

Work of women in one day = Women in ratio × Given Women in 16 hectare

Work of women in one day = 4 × 4

Work of women in one day = 16

For children

Work of children in one day = Children in ratio × Given Children in 16 hectare

Work of children in one day = 2 × 7

Work of children in one day = 14

By using same formula

(Men + Women + Children) × Time/Field reaped

(30 + 16 + 14) × T/16

60T/16

Comparing both

300/10 = 60T/16

300 × 16/10 × 60 = T

5 × 16/10 = T

80/10 = T

8 = T

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Answered by sharmavaikunth4
0

Answer:

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