Math, asked by mpmahor, 1 month ago

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Answered by sharma78savita
2

Answer:

Answer Is (A) 0, 1

Step-by-step explanation:

And pq=q

q(p−1)=0

⇒q=0 or p=1

So, by (1), q=0⇒p=0

Hence, the values of p are 0,1.

Answered by gorachandhansda405
2

Answer:

(A) 0,1

Step-by-step explanation:

  • Here,
  • given equation = x^2 + px + q
  • Also, given that p,q are the roots of the equation.
  • So, p+q = -p
  • p+p = -q
  • 2p = -q ..........(1)
  • And pq = q
  • pq -q = 0
  • q (p-1) = 0
  • Therefore, q = 0 & p-1 = 0 =>p = 1
  • Now, by (1) q = 0
  • p = -q/2 = -0/2 = 0
  • Hence,value of p is 0,1.
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