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Answered by
2
Answer:
Answer Is (A) 0, 1
Step-by-step explanation:
And pq=q
q(p−1)=0
⇒q=0 or p=1
So, by (1), q=0⇒p=0
Hence, the values of p are 0,1.
Answered by
2
Answer:
(A) 0,1
Step-by-step explanation:
- Here,
- given equation = x^2 + px + q
- Also, given that p,q are the roots of the equation.
- So, p+q = -p
- p+p = -q
- 2p = -q ..........(1)
- And pq = q
- pq -q = 0
- q (p-1) = 0
- Therefore, q = 0 & p-1 = 0 =>p = 1
- Now, by (1) q = 0
- p = -q/2 = -0/2 = 0
- Hence,value of p is 0,1.
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