Question

Answer!!


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Answer 1

• Option (ii) is your answer

For Solution refer to the attachment!!

Answer 2

Step-by-step explanation:

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Given Equation,

${x}^{2} + px + q$

And,

Also given, p & q are the roots of the equation.

Since,

p + q = -p

2p = -q _._._._( 1 )

And, pq = q

Therefore,

q ( p - 1 ) = 0

=> q = 0 OR p = 1

So,

By 1 Equation, q = 0 => p = 0

Hence,

The values of p are = 0 & 1

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