Math, asked by techboy53, 7 months ago

answer any four of the following
pls someone solve this​

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Answers

Answered by sreeh123flyback
1

I'm answering 2,3,4,1 okkkk

1)

C.I=615

A=p(1+R/100)^n

C.I=A-p

C.I=P(1+R/100)^n - P

615=P((1+R/100)^n - 1)

615=P((1+5/100)² - 1)

615=P((1+1/20)² - 1)

615=p((20+1/20)² - 1)

615=p((21/20)² - 1)

615=p((441/400 ) - 1)

615=p(441-400/400)

615=p(41/400)

615×400=41×p

p=(615×400)/41

P= 6000¥

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