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E has half number of electrons in its fourth shell then its first shell means it has 1 electron in its 4 shell and it has same number of electrons in its 2nd and 3rd shell that is 8 so the elementsl is potassium (K)
1) Electronic configuration of element E is
2,8,8,1
2) Valency of E is 1
3) group = 1st
period = 4th
4) The nature of oxide of E is Basic or Alkaline and it is a metal oxide.
5) compound formed = KX
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