Math, asked by aamilnasseer38065, 1 month ago

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Answered by simi20010111
0

Answer:

2. \: 7 \sqrt{2}   - 2 \sqrt{3}

3. \: (5 +  \sqrt{8}) + (3 -  \sqrt{2}) - (6 +  \sqrt{2} ) \\  = (5 + 2 \sqrt{2}) + (3 -  \sqrt{2}) - (6 +  \sqrt{2} )  \\  = (5 + 3 - 6) + (2 \sqrt{2 }  -  \sqrt{2} -  \sqrt{2} ) \\  = (8 - 6) + (2 \sqrt{2 }  -  2\sqrt{2} ) \\  = 2 + 0 = 2

4.true

6. \: irrational \: number

7. \: ( 3 +  \sqrt{2} ) \: ( 4 +  \sqrt{3} ) \\  = (12 +  3\sqrt{3}  + 4 \sqrt{2 }   + \sqrt{6} )

 8 .\frac{4 \sqrt{28} }{3 \sqrt{7} }  \\  \frac{4}{3}  \times  \sqrt{4 } =  \frac{4\sqrt{4}  }{3}

Answered by Anonymous
2

Answer:

4: true

Step-by-step explanation:

0 is a rational no. because it can be written in the form of 0/1 where 0 and 1 are integers and denominator is not equal to 0

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