Question

answer anyone please​

Answer 1

Step-by-step explanation:

hope it helps!!!!! thanks

Answer 2

$(coecA - sinA)(secA - cosA) \\ \\ = \frac{1 - {sin}^{2}A }{sinA} \times \frac{1 - {cos}^{2}A }{cosA} \\ \\ = \frac{ {cos}^{2} A \times {sin}^{2} A}{sinAcosA} \\ \\ = sinAcosA \\ \\ = \frac{1}{ \frac{1}{sinAcosA} } \\ \\ = \frac{1}{ \frac{ {sin}^{2}A + {cos}^{2} A }{sinAcosA} } \\ \\ = \frac{1}{ \frac{sinA}{cosA} + \frac{cosA}{sinA} } \\ \\ = \frac{1}{tanA + cotA}$