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Answer:
a) 4%
Explanation:
the detailed answer is in the attachment. Hope it helps.
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The volume of the wire is given by, V=πr²l
Thus density of the wire, ρ=m by πr²l
Taking log and then differentiate:
⟹
ρ
Δρ
×100=
m
Δm
×100+2
r
Δr
×100+
L
ΔL
×100
∴
ρ
Δρ
×100=
0.3
0.003
×100+2
0.5
0.005
×100+
6
0.06
×100=4%.
⟹ Percentage error in density is 4%.
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