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Given :
height of the waterfall ( h ) = 50 m
Initial temperature ( t₁ ) = 15°C
Heat energy = kinetic energy of the water
Heat energy = m c Δ t
Kinetic energy = m g h
Hence we get :
m c Δ t = m g h
Cancel m both sides :
==> c Δ t = g h
We know that c of water is 4.2 cal / g °C
Also : Δ t = t - t₁
So : 4.2 × Δ t = 10 × 50
==> Δ t = 500 / 4.2
==> Δ t = 5000 / 42
==>Δ t = 134.047
The change in temperature is 134.05 K
Hope it helps !
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