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In ∆OBC and ∆OAD
BC=AD(given)
angleOAD= angleOBC(90° each)
angle BOC=angleAOD( vertical opposite angle)
So, ∆OBC congruent to ∆OAD (by AAS)
BO=AO(CPCT)
hope this helps
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BC=AD(given)
angleOAD= angleOBC(90° each)
angle BOC=angleAOD( vertical opposite angle)
So, ∆OBC congruent to ∆OAD (by AAS)
BO=AO(CPCT)
hope this helps
Mark as Brainlist
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