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Answer 1

Answer:

65487 s

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Answer 2

Step-by-step explanation:

$\frac{6 {(8)}^{n + 1} + 16 {(2)}^{3n - 2} }{10 {(2)}^{3n + 1} - 7 {(8)}^{n} } \\ = \frac{6 {[ {(2)}^{3} ]}^{n + 1} + 16 {(2)}^{3n - 2} }{10 {(2)}^{3n + 1} - 7 { [{2}^{3}] }^{n} } \\ = \frac{6 {(2)}^{3n + 3} + 16 {(2)}^{3n - 2} }{10 {(2)}^{3n + 1} - 7 {(2)}^{3n} } \\ = \frac{6 \times {2}^{3n} \times {2}^{3} + 16 \times {2}^{3n} \times {2}^{ - 2} }{10 \times {2}^{3n} \times 2 - 7 \times {2}^{3n} } \\ = \frac{ {2}^{3n}(6 \times {2}^{3} + 16 \times {2}^{ - 2} )}{ {2}^{3n} (10 \times 2 - 7)} \\ = \frac{6 \times 8 + 16 \times \frac{1}{4} }{10 \times 2 - 7} \\ = \frac{48 + 4}{20 - 7} \\ = \frac{52}{13} \\ = 4$