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Answer 1

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♧Question♧

• A simple pendulum of length l carries a bob of mass m. if the breaking strength of the string is 2mg,the maximum angular amplitude from the vertical can be_________

♧Answer♧

Given data:-

• ➠Strength of the string = 2mg

To find:-

• ➠Maximum angular amplitude = ?

Solution:-

☆As we know , the maximum tension is at the lowest point.

• ➠Tmax = 2 m g
• ➠T- mg = mv²/l
• ➠2mg – mg = mv²/l
• ➠v = √(gl)

☆By applying energy conservation.

• ➠mgh = mv²/2
• ➠mgl ( 1 - cosθ ) = (m/2)(√(lg))²
• ➠gl- glcosθ = (m/2)(√(lg))²
• ➠gl/2 = glcosθ
• ➠1/2 = cosθ
• ➠θ = 60° Ans

So the Maximum angular amplitude from its vertical can be 60°.

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