Question

answer as soon as possible please

Answer 1

a) Area of the path = Area of IJKL+Area of RFGH - area of MNOP

=>area of IJKL = (17*1)m^2
=>17 m^2

Area of EFGH = (12*0.5)m^2
=>6m^2


Area of MNOP =(1*0.5)m^2
=>0.5m^2

Hence, area of the path = 17+6-0.5
=>22.5m^2

b)Cost of laying grass on the path = Rs. 22.5*5
=>Rs. 112.5

c) Cost of tiling the path =Rs. 22.5*10
=>Rs. 225