Question

answer as soon as possible please ​

Answer 1

SIMPLIFICATION :-

${[ ({2})^{ - 1} + {(4)}^{ - 1} + {(3)}^{ - 1} ]}^{ - 1} \\ \\ = {[\frac{1}{2} + \frac{1}{4} + \frac{1}{3}]}^{ - 1} \\ \\ = { (\frac{6 + 3 + 4}{12} )}^{ - 1} \\ \\ = { (\frac{13}{12}) }^{ - 1} \\ \\ = \boxed{ \frac{12}{13} }$

RULES USED :-

${(\frac{x}{y}) }^{ - d} = { (\frac{y}{x} )}^{d}$