answer asap.........
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(i) x+ 1/x =3
x²+1/x =3
x²+1 =3x
x²-3x+1=0
a= 1 b=-3 c=1
D=b²-4ac=(-3)²-4(1)(1)=9-4=5
x=-b+√D/2a or -b-√D/2a
=-(-3)+√5/2 or -(-3)-√5/2
=3+√5/2 or 3-√5/2
(ii) 1/x -1/x-2 =3
x-2-x/x²-2x=3
-2=3x²-6x
3x²-6x+2=0
a=3 b=-6 c=2
D=b²-4ac
=(-6)²-4(3)(2)
=36-24
D=12
x=-b+√D/2a or -b-√D/2a
=-(-6)+√12/2(3) or -(-6)-√12/2(3)
=6+2√3/6 or 6-2√3/6
=1+ √3/3 or 1- √3/3
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Answer:
answer for the given problem is given by using Sridharacharya formula
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