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the coordinates of the points of intersection of lines ax+by=9 and bx+ay=5 is (3,minus 1). find the values of a and b
ax+by=9
bx + ay = 5
as both lines intersect on point (3,-1)
so this point lies on both line hence
satisfies the line equation
3a - b = 9
3b - a = 5
adding both
2a +2b =14
a + b = 7
b = 7-a
3a -(7-a) = 9
4a - 7 = 9
4a = 16
a = 4
b = 7-4 = 3
a = 4
b = 3
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