Answer ASAP
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Hello mate,
Here,
ang.APB+ang.OAP+ang.OBP+ang.AOB=360°
or, 40°+90°+90°+ang.AOB=360°
or, ang.AOB=360°-220°=140°
As, ang.ACB=(ang.AOB)/2
Hence, ang.ACB = 70° answer.....
Thank you! !
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