Question

Answer

Atomic number of Sodium(Na) atom is 11. 
Electronic configuration is : 
Na = 2, 8, 1 
So it contains 1 valence electron. In order to achieve the nearest noble gas configuration, it loses one electron to form Sodium ion. 
Na+=2,8 


Atomic number of Chlorine(Cl) atom is 17. 
Electronic configuration is : 
Cl = 2, 8, 7 
So it contains 7 valence electron. In order to achieve the nearest noble gas configuration, it gains one electron to form Chloride ion. 
Cl−=2,8,8

  
An Ionic bond is formed between sodium ion and chloride ion by complete transfer of electron from sodium to chlorine. 

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Answer 1

Answer:

Answer

Atomic number of sodium is 11, it has following electronic configuration: 2(K),8(L),1(M). Sodium atom donates one electron in its valence shell M, which results in disappearance of M shell and its L shell with eight electrons becomes new valence shell. Thus, it attains the stable electronic configuration of nearest noble gas neon.