Question

answer batao...........xd​

Answer 1

Answer:

43

Solution:

Let,

• one shoe be x
• man be y
• one cone be z

From first equation

⇒ 2x + 2x + 2x = 30

⇒ 6x = 30

⇒ x = 30 / 6

⇒ x = 5

From second equation

⇒ y + y + 2x = 20

⇒ 2y + 2x = 20

⇒ 2( y + x ) = 20

⇒ y + x = 20 / 2

⇒ y + x = 10

⇒ y = 10 - x

⇒ y = 10 - 5

⇒ y = 5

From third equation

⇒ 2z + 2z + y = 13

⇒ 4z + 5 = 13

⇒ 4z = 13 - 5

⇒ 4z = 8

⇒ z = 8 / 4

⇒ z = 2

From fourth equation

⇒ x + ( 2x + y + 2z ) × z = ?

⇒ 5 + { 2( 5 ) + 5 + 2( 2 ) } × 2 = ?

⇒ 5 + ( 10 + 5 + 4 ) × 2 = ?

⇒ 5 + 19 × 2 = ?

⇒ 5 + 38 = ?

⇒ 43 = ?

⇒ ? = 43

Therefore the answer is 43.

Answer 2

AnswEr:

required value is 43.

ExplanaTion:

From 1st line, we get,

10 + 10 + 10 = 30

One pair of shoes = 10

From 2nd line, we get,

5 + 5 + 10 = 20

One boy = 5

From 3rd line, we get,

4 + 4 + 5 = 13

One bouquet = 2

$\rule{200}2$

Now, in 4th line,

a shoe ( 5 ) + boy wearing a pair of shoes with a pair of bouquet ( 5 + 4 + 10 ) × a bouquet ( 2 )

$\implies$ 5 + 19 × 2

$\implies$ 5 + 38

: $\implies$ 43.

Hence, required value is 43.