Question

answer be long method..
spammers get far. ​

Answer 1

Answer=1080.56

SI=>Simple interest

First convert the time in years

$1 \: year \: 3 \: months \: = 1 \times \frac{3}{12} year \: = 1 \times \frac{1}{4}$

Putting the values in the know formula and then

$a = 10000(1 + \frac{17}{200} ) 1 \times \frac{1}{4}$

Now find the amount for whole part,i.e.,1year in this case, then use the principal to get the SI (simple interest) for

$\frac{1}{4} year \: more$

$a = 10000(1 + \frac{17}{200} ) \\ = 10000 \times \frac{217}{200} = 10850$

Now this would act as the principal for

$next \: \frac{1}{4} year \: .we \: find \: the \: si \: on \: 10850 \: for \: \\ \frac{1}{4} year$

$si = \frac{10850 \times \frac{1}{5} \times 17 }{100 \times 2} \\ = \frac{10850 \times 1 \times 17}{800} = 230.56$

$intrest \: for \: first \: year = 10850 - 10000\\ = 850 \\ and \: intrest \: for \: next \: \frac{1}{4} year \: = 230.56 \\ therefore..total \: compound \: intrest \: \\= 850 + 230.56 = 1080.56$

Answer 2

hope it is helpful to you