Question

answer both fastly ​

Answer 1

Step-by-step explanation:

15.px²+qx+r=0 has equal roots

so ∆=0....where∆=b²-4ac

q²-4pr=0

q²=4pr

16. same as 15

∆=0

(-2b(a+c))²-4(a²+b²)(b²+c²)=0

4b²(a²+c²+2ac)-4(a²b²+a²c²+b⁴+b²c²)=0

4a²b²+4b²c²+8b²ac-4a²b²-4a²c²-4b⁴-4b²c²=0

8b²ac-4a²c²-4b⁴=0

hence the required relation

hope it helps u