Answer both of the following questions:
(a) The four angles of a quadrilateral are
as 2:4:1:5. Find the angles.
(b) Is an equilateral triangle a regular
polygon?
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Consider the angles of a quadrilateral as 2x, 4x, 5x and 7x In a quadrilateral we know that the sum of all the angles is 360o So we can write it as 2x + 4x + 5x + 7x = 360o By addition 18x = 360o By division xo = 20o Now by substituting the value of xo 2x = 2(20o) = 40o 4x = 4(20o) = 80o 5x = 5(20o) = 100o 7x = 7(20o) = 140o Therefore, the angles are 40o, 80o, 100o and 140o.
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