Question

ANSWER BOTH QUESTION S AT SAME TIME PLS​

Answer 1

Answer:

1. In figure 1,

50 + 60 + y = 180 ( sum of angles on straight line)

110 + y = 180

y = 180 - 110

y = 70

y + z = 180 ( interior angles)

70 + z = 180

z = 180 - 70

z = 110

y + 60 + x+ 25 = 180 ( interior angles )

70 + 60 + x + 25 = 180

130 + 25 + x = 180

155 + x = 180

x = 180 - 155

x = 125

Therefore , x = 125 , y = 70 and z = 110

2. In figure 2,

BEF = PEG = 70 ( VERTICALLY OPPOSITE ANGLES)

BEF + DFB = 180 ( INTERIOR ANGLES )

70 + DFB = 180

DFB = 180 - 70

DFB = 110

QFH = DFB ( VERTICALLY OPPOSITE ANGLES)

QFH = 110

QFH + PQR = QHC

QFH + PQR = 140

110 + PQR = 140

PQR = 140 - 110

PQR = 30