Answer both the questions in the attachments
Answers
Answer:
Q2.
- i) d) Parabola
As, the given graph has a vertex and its a key feature if parabola that it's got one vertex and opens on the other end.
- ii) a) 2
Since, the given graph intersects the x- axis at 2 points it has 2 zeroes.
Zeroes of an equation are the points on the graph of that equation where the graph meets the x- axis.
- iii) b) -1, 4
As the parabola intersects the x- axis at points x = -1 and x = 4. The zeroes become -1 and 4
- iv) c) x² - 3x - 4
solving option c :-
Let, y = x² - 3x - 4
=> y = x² - 4x + x - 4
=>y = x(x - 4) + 1(x - 4)
=> y = (x + 1)(x - 4)
For y to be zero,
Either x = -1
or x = 4
And, from the graph at x = -1 and x = 4 the value of y is 0.
Hence, the equation of this polynomial is x² - 3x - 4
- v) d) 0
From earlier points, we know that x = -1 is a zero of the polynomial and hence the value of the expression at x = -1 is 0.
Q3)
The given quadratic polynomial is :-
y = x² + 2x - 3
- putting x = -4
=> y = (-4)² + 2(-4) - 3 => 16 - 8 - 3
=> y = 5
- putting x = -3
=> y = (-3)² + 2(-3) - 3 => 9 - 6 - 3
=> y = 0
- putting x = -2
=> y = (-2)² + 2(-2) - 3 => 4 - 4 - 3
=> y = -3
- putting x = -1
=> y = (-1)² + 2(-1) - 3 => 1 - 2 -3
=> y = -4
- putting x = 0
=> y = (0)² + 2(0) - 3 => -3
=> y= -3
- putting x = 1
=> y = (1)² + 2(1) - 3 => 1 + 2 - 3
=> y = 0
- putting x = 2
=> y = (2)² + 2(2) - 3 => 4 + 4 - 3
=> y = 5
Hope this helps!
Step-by-step explanation:
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