Math, asked by karanneginegi480, 11 months ago

answer btado pls... board h​

Attachments:

Answers

Answered by veenrpni1995
1

Answer:nice handwriting

Step-by-step explanation:

Answered by sakshi000152
1

Answer:

Sides of both the squares are 61.5 and 55.5

Step-by-step explanation:

Sum of two perimeters of square = 468 sq. m

4s + 4a = 468 ......(i)

4s - 4a = 24 ......(ii)

By adding both equations ,we get

(4s + 4a) + (4s- 4a) = 468 + 24

4s + 4a + 4s - 4a = 492

8s = 492

s = 492/8

s = 123/2

s = 61.5

Perimeter of first square = 4s = 4× 61.5 = 246

Since, 4s - 4a = 24

So, 246 - 4a = 24

246 - 24 = 4a

222 = 4a

a = 55.5

Perimeter of second square = 4a = 4× 55.5 = 222

Side of first square = 61.5 and side of second square = 55.5

Hope it helps u...

Mark as brainliest.....

Similar questions