Question

answer correctly.....all the questions​

Answer 1

$\mathcal{\huge{\blue{\underline{\underline{AnswEr}}}}}$

★Density = Mass/Volume

Mass = Density x Volume

Mass = 3000 Kg/m3×5m3 = 15000 Kgs.

_____________________________

Given :-

Mass = 63 gm

Density = 9 gm/cm³

To Find :-

Volume

SoluTion :-

As we know,

$\sf {\rho = \frac{m}{v} }$

So,

$\sf {v=\frac{m}{\rho} }\\\\\\\sf {v=\frac{63}{9} }\\\\\\\sf {v=7\ cm^{3}}$

_______________________________

★use formula as same as first one

___________________________

Length of cuboid = 500 cm = 5 m

Width of cuboid = 200 cm = 2 m

Height of cuboid = 1.6 m

Volume of cuboid = 5 * 2 * 1.6

= 16 m^3

____________________________

Average=sum of observations ÷ number of observations.

So,A =(50+40+30)÷3

=120÷3

=40

So, the average speed of the boy is 40m per 10 seconds

Answer 2

Density = Mass/Volume

Mass = Density x Volume

Mass = 3000 Kg/m3×5m3 = 15000 Kgs.

_____________________________

Given :-

Mass = 63 gm

Density = 9 gm/cm³

To Find :-

Volume

SoluTion :-

As we know,

\sf {\rho = \frac{m}{v} }ρ=

v

m

So,

$$\begin{lgathered}\sf {v=\frac{m}{\rho} }\\\\\\\sf {v=\frac{63}{9} }\\\\\\\sf {v=7\ cm^{3}}\end{lgathered}$$

_______________________________

★use formula as same as first one

___________________________

Length of cuboid = 500 cm = 5 m

Width of cuboid = 200 cm = 2 m

Height of cuboid = 1.6 m

Volume of cuboid = 5 * 2 * 1.6

= 16 m^3

____________________________

Average=sum of observations ÷ number of observations.

So,A =(50+40+30)÷3

=120÷3

=40

So, the average speed of the boy is 40m per 10 seconds