Question

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Answer 1

Explanation:

Correct option is

D

7

5π

Let ∠A=θ

⇒∠APQ=θ(∵AQ=PQ)

⇒∠PQB=2θ(∵ Exterior angle)

⇒∠PQB=∠PQB=2θ(∵PQ=PB)

⇒∠BPC=∠A+∠ABP=3θ(∵ Exterior angle)

⇒∠BCP=∠BPC=3θ(∵BP=BC)

Also ∠ABC=∠ACB=3θ(∵AB=AC)

⇒∠A+∠B+∠C=θ+3θ+3θ=7θ=π⇒θ=

7

π

.

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