Question

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Answer 1

Answer:

Let maximum velocity of athlete is v.

initial velocity of athlete , u = 0

distance travelled by athlete with an acceleration 2 m/s² is s

use formula, v² = u² + 2as

v² = 0 + 2 × 2 × s = 4s .......(1)

athlete decelerates and comes to rest.

so, final velocity of athlete, v' = 0

initial velocity of athlete , u = v

distance travelled by athlete is (100 - s)

use formula, v² = u² + 2as

0 = v² - 2 × 3 × (100 - s)

v² = 6(100 - s) ..........(2)

from equations (1) and (2),

4s = 6(100 - s)

4s = 600 - 6s

4s + 6s = 600

10s = 600

s = 60 m

so, v² = 4s = 4 × 60 = 240

v =

Explanation: