Question

answer correctly.....or.....please... only this one is enough....​

Answer 1

Answer:

Let the distance, for convenience of calculation, be 60 metres, so at 20 m/sec the first half (30 m) takes 1.5 seconds (30/20), the second half takes 1 second (30/30). Total time 2.5 seconds, total distance 60 metres (assumed), so average speed is 60/2.5; you work that out. The distance we assume is for convenience of calculation only and obviously cancels out. You would get the same result by assuming any convenient distance to work with or just call it "x".

Explanation:

Average velocity is total displacement divided by total time.

Average speed is total distance divided by total time.

In this case, since the travel is in the same direction, they are the same.

First half, time is d/20

second half, time is d/30

total time is (d/20) + (d/30) = d((1/20) + (1/30)) = d((3/60) + (2/60))

total time = d(5/60) = d/12

total distance = 2d

Average velocity = 2d/(d/12) = 24 m/s

Answer 2

Explanation:

$\bf\huge{Question:-}$

$\bf\huge{answer:-}$

$\bf\ refer \ the \ attachment$