Math, asked by farhathmanas13, 5 months ago

answer correctly pls

(6ab+2) (2a+2)​

Answers

Answered by sittus573
0

Equation at the end of step 1

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2)

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2:

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:STEP

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:STEP4

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:STEP4:

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:STEP4:Pulling out like terms

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:STEP4:Pulling out like terms 4.1 Pull out like factors :

Equation at the end of step 1 (6a • (b2)) - (0 - 2a2) STEP 2 :Equation at the end of step2: (2•3ab2) - -2a2STEP3:STEP4:Pulling out like terms 4.1 Pull out like factors : 2a2 + 6ab2 = 2a • (a + 3b2)

Answered by ipshadey65
1

Step-by-step explanation:

(6ab+2)(2a+2)

[(6ab x 2a)+(6ab x 2)][(2 x 2a)+(2 x 2)]

[(12a^2 b + 12ab)][4a+ 4]

12a^2 b + 12ab+ 4a +4

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