Question

answer fast ........ ​

Answer 1

A driver accelerates his car first at the rate of 1.8 m/s^2 and then at the rate of 1.2 m/s^2. calculate the ratio of force exerted by the engine in the two cases

Answer:

3:2

Explanation:

F1/F2 = ma1/ma2 = 1.8/1.2 = 18/12 = 3/2 = 3:2

Answer 2

given :

a1=1.8m/s^2

a2=1.2m/s^2

WKT F=ma

=) F1/F2 =ma1/ma2

=) F1/F2 =a1/a2 (m gets cancel; coz it

is same in both

cases)

=) F1:F2 = 1.8/1.2

=) F1:F2=0.3/0.2

=) F1: F2=3/2 (multiply by 10 in both

numerator&

denominator)

=) F1:F2 = 3:2