Question

answer fast and correct ok ok​

Answer 1

Answer:

1) d

2)c

hope it helps you

Answer 2

1. (C) 4

x = 2 + √3

$\sf{\dfrac{1}{x} =\dfrac{1}{2+\sqrt{3}} }\\\\\sf{\implies \dfrac{1}{x}=\dfrac{2-\sqrt{3} }{(2+\sqrt{3} )(2-\sqrt{3})} }\\\\\sf{\implies \dfrac{1}{x}=\dfrac{2-\sqrt{3} }{(2)^2-(\sqrt{3})^2} }\\\\\sf{\implies \dfrac{1}{x} =\dfrac{2-\sqrt{3} }{4-3} }\\\\\sf{\implies \dfrac{1}{x} =\dfrac{2-\sqrt{3} }{1} }\\\\\sf{\implies \dfrac{1}{x} =2-\sqrt{3} }$

$\sf{x+\dfrac{1}{x} =2+\sqrt{3}+2-\sqrt{3}}\\\\\sf{x+\dfrac{1}{x} =2+2}\\\\\boxed{\sf{x+\dfrac{1}{x} =4}}$

$\rule{200}2$

2. (C) y

y can be expressed as y¹ which is obviously a polynomial.