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bansalpalak394:
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Explanation:
a) The velocity particle become constant after 10s which is 20m/s and velocity after 40s is zero because particle arrived to his initial point and displacement becomes zero.b) The distance covered between 10th and 30th sec is area under the graph which is = area of square=s^2 = 20×20 =400m^2 c) Total area under the graph will total distance covered = area of trapezium= 1/2× sum of parrellel sides ×height= 1/2× 60×20 = 600m^2
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