Question

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Answer 1

Seg AD is the median of triangle ABC,

AD = DC = 1/2 BC,

In triangle AMD,

by pythagoras theorem,

AD2 = AM2 + MD2,

In triangle AMC,

by pythagoras theorem,

AC2 = AM2 + MC2,

AC2 = AM2 +(MD + DC)2

AC2 = AM2 + MD2 + 2MDxDC + DC2

AC2 = (AM2 + MD2) 2MDxDC + DC2

AC2 = AD2 + 2MDxBC/2 + (BC/2)2

AC2 = AD2 + MDxBC + (BC/2)2