Question

answer fast argent easy​

Answer 1

Answer:

area of a door 3×2=6

area of a wall 10×10= 100

area of remaining part of painting = Area of wall

area of door

= 100-6

= 94

labour's charge for painting = 94 sqm = 94× 2.5

= 235

So, rs 235 is required for painting the wall

Answer 2

Answer:

area of door frame = 3m×2m

$6 {m}^{2}$

area of wall = 10m×10m

$100 {m}^{2}$

thus, area of remaining wall is

$100 {m}^{2} - 6 {m}^{2}$

$= 94 {m}^{2}$

thus, total labour charges is

2.50×94. = 235rs.