Question

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Answer 1

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Answer 2

$\underline{\mathfrak{\huge{The\:Question:}}}$

Given are the lengths of a torch light, in the figure. Find the curved surface area of the torch light.

$\underline{\mathfrak{\huge{Your\:Answer:}}}$

The Curved Surface Area of the cylinder = $\tt{2\pi r h }$

=》 Curved Surface Area of the cylinder = $\tt{2 \times \frac{22}{7} \times 7 \times (26 - 5)}$

We did : Height of the cylinder = 26 - 5 ( cm ) since the total length of the torch light is 26 cm and the height of the circular part of the torch light is 5 cm

=》 Curved Surface Area of the cylinder = 2 × 22 × 21

=》 Curved Surface Area of the cylinder = $\tt{924 cm^{2}}$

The Curved Surface Area of the circular part = $\tt{2\pi r h}$

=》 Curved Surface Area of the circular part = $\tt{2\times \frac{22}{7} \times 14 \times 5}$

=》 Curved Surface Area of the circular part = 2 × 22 × 2 × 5

=》 Curved Surface Area of the circular part = $\tt{440 cm^{2}}$

Total curved surface area of the torch light = 924 + 440 $(cm^{2})$

Total curved surface area = $\tt{1364 cm^{2}}$