Question

Answer fast both the questions IPM maths so kids stay away. Don't spam or else I'll report u. ​

Answer 1

OA = OB = Radius

Area of ΔAOB = (1/2) * OA * OB = 32

=> Radius * Radius = 64

=> Radius² = 8²

=> Radius = 8 cm

OA = OB = 8 cm

AB² = OA² + OB²

=> AB = 8√2 cm

Let say M is mid point of AB

then AM = BM  = 4√2

OM = 4√2   ( as OM² = OA² - AM²)

AD = BD   => DM will pass through center of circle O

DM ⊥ AB

DM = DO + OM    or   DO - OM  ( depending on position of D)

DO = Radius = 8 cm

DM = (8 + 4√2)  or (8 - 4√2)

Area of ΔABD = (1/2) AB * DM

= (1/2) (8√2) (8 + 4√2)     or (1/2) (8√2) (8 - 4√2)

= 32√2 + 32    or      32√2 - 32