Question

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Answer 1

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Answer 2

Let the cost of 1 shirt be 'x'

The cost of 12 shirts = Rs.$3600 \frac{2}{5}$= $Rs . \frac{3600 \times 5 + 2}{5} = Rs. \frac{18002}{5}$

12x = $Rs \: \frac{18002}{5}$

$x = \frac{18002}{5 \times1 2} = \frac{9001}{30}$

Let the cost of 1 pant be 'y'

Cost of 6 pants , 6x = $Rs.3000 \frac{3}{4} = Rs. \: \frac{3000 \times 4 + 3}{4} = Rs. \: \frac{12003}{4}$

Cost of 1 pant , x = $\frac{12003}{4 \times 6} = Rs. \frac{4001}{8}$

Cost of 4 shirts and 4 pants,

$4x + 4y = 4 \times \frac{9001}{30} + 4 \times \frac{4001}{8} \\ \\ = \frac{18002}{15} + \frac{4001}{2} \\ \\ = 1200.13 + 2000 \\ \\ = Rs. 3200$