Question

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Answer 1

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QUESTION :

A train starting from a railway platform and moving with an uniform Acceleration attains a speed of 40 km hr in 10 minutes.

Find its acceleration ..

SOLUTION :

This train startes from the railway platform.

So it's innitial velocity, u = 0 m / s

It attains a speed of 40 kmph

40 kmph = 40 × { 5 / 18 } m / s

=> 11.1 m / s approx.

Time = 10 minutes = 600 seconds.

Now using the Newton's first Equation of motion :

Acceleration = { V - U } / t

=> A = 11.1 / 600 m / s ^ 2

Acceleration = 0.185 m/s ^ 2 approx.

ANSWER :

The acceleration of the train is approximately 0.185 m / s ^ 2.

ADDITIONAL INFORMATION :

The two other equations of motion are :

S = ut + { 1 / 2 } a t ^ 2

V ^ 2 = U ^ 2 + 2AS

Here,

U stands for innitial velocity

V stands for final velocity.

A stands for acceleration.

S stands for displacement.

T stands for time.

Answer 2

Answer:

a= 0.01851 m/s2

Explanation:

we know that :

acceleration = velocity / time

v = 40 km/ hr

in MKS system

= 100/9 m / s

t = 10 min

in MKS system

= 600 sec

a = 100/9×600. = 0.01851 m / s2

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