Question

Answer fast. Give appropriate answers only as it's a request.​

Answer 1

Step-by-step explanation:

The dimensions of room is 12×8×4

The Lateral surface area is

2h(l+b)

2(4)(12+8)

8×20=160m ^2

Cost of white wash is 5m ^2

Total cost is 5×160=800Rs,

______________________-______

Area of ceiling = 12*8 = 96 sq m

So, cost = rs 5 * 96

= rs. 480

Total cost = 800+480

=rs.1280

Answer 2

Answer:

Length of room = 12m

Width of room =8m

Area of four walls of room = Perimetre of base X Height of room

=2(l+b)h

=2(12+8)X4=160m^2

Cost of whitewashing per m^2=Rs5

Area of ceiling =12X8=96m^2

Cost of whitewashing ceiling =(96X5)=Rs480

Cost of whitewashing=Rs=(800+480)=Rs