Question

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Answer 1

Question :-

Two parallel sides of a trapezium are 25 cm and 35 cm. Find it's area if meausre of the distance between parallel sides is 12 cm.

Answer :-

We know that,

Area of trapezium = ½ × ( sum of parallel sides ) × height

• Parallel sides = 25 cm and 35 cm

• Distance between parallel sides i.e. Height = 12 cm

Substituting the value in formula :-

→ Area = ½ × ( 25 + 35 ) × 12

→ Area = ½ × 60 × 12

→ Area = 360

Area of trapezium = 360 cm²

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

Answer 2

Answer:

Area of trapezium =1/2×sum of parallel sides×distance between

1/2×25+35×12=

1/2×60×12=360