Question

answer fast!!!
How many molecules are present in 9 grams of water and 17 grams of ammonia?

Answer 1

no of moles of water = 9 g / 18 g =1/2 moles
so no of molecules present = no of moles × N(A)
=1/2 × 6.022×10^23
= 3.011×10^23
no of moles = 17/17= 1 mole
no of molecules = 1 × 6.022× 10^23
=6.022×10^23

Answer 2

Water has 18 grams per mole so 9 grams is 0.5 moles of water. There are6.022* 10^23 molecules in a mole. Each water molecule contains one oxygen and two hydrogens.Ammonia, formed of 3 hydrogen atoms and a nitrogen atom, has an atomic weight of 17g/mol. (Actually 17.031g/mol if we’re being picky.)

This means that 17g of ammonia is one mole of ammonia.

The number of molecules in a single mole of any compound is given by Avoadro’s constant, which is 6.023x10^23.