Question

answer fast i am giving 100 credits​

Answer 1

Answer:

Step-by-step explanation:

cosec x=cosec 2x+cosec 4x

1/sinx=1/sin 2x+1/sin 4x

sin 2x*sin 4x/sin x=sin 2x+sin 4x

Sin C+Sin D=2 Sin (C+D/2) Cos(C-D/2)

Sin 2x=2 Sinx Cosx

2*sinx*cosx*sin 4x/sinx=2 sin (3x) cos (x)

2 cosx sin 4x=2 sin(3x) cos(x)

cos(x) {sin 4x-sin 3x}=0

Sin C-sin D= 2 cos (C+D/2) sin (C-D/2)

2 cos(x) {sin(x/2) cos(7x/2)}=0

• Cosx=0 ==== x=(2n+1)$\pi$/2

• Sin(x/2)=0===== x=2n$\pi$
• cos(7x/2)=0===== 7x/2=2n+1($\pi$/2)
•                            x=2/7 (2n+1)($\pi$/2)
• Where n∈Z
•    

I hope it is clear...

please mark as brainliest and thank if it helps...